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-rw-r--r--cpukit/score/src/schedulersimplereadyqueueenqueuefirst.c26
1 files changed, 2 insertions, 24 deletions
diff --git a/cpukit/score/src/schedulersimplereadyqueueenqueuefirst.c b/cpukit/score/src/schedulersimplereadyqueueenqueuefirst.c
index 47a4a3be64..c5ee8ebe12 100644
--- a/cpukit/score/src/schedulersimplereadyqueueenqueuefirst.c
+++ b/cpukit/score/src/schedulersimplereadyqueueenqueuefirst.c
@@ -27,29 +27,7 @@ void _Scheduler_simple_Ready_queue_enqueue_first(
Thread_Control *the_thread
)
{
- Chain_Control *ready;
- Chain_Node *the_node;
- Thread_Control *current;
+ Chain_Control *ready = (Chain_Control *) _Scheduler.information;
- ready = (Chain_Control *)_Scheduler.information;
- current = (Thread_Control *)ready;
-
- /*
- * Do NOT need to check for end of chain because there is always
- * at least one task on the ready chain -- the IDLE task. It can
- * never block, should never attempt to obtain a semaphore or mutex,
- * and thus will always be there.
- */
- for ( the_node = _Chain_First(ready) ; ; the_node = the_node->next ) {
- current = (Thread_Control *) the_node;
-
- /* break when AT HEAD OF (or PAST) our priority */
- if ( the_thread->current_priority <= current->current_priority ) {
- current = (Thread_Control *)current->Object.Node.previous;
- break;
- }
- }
-
- /* enqueue */
- _Chain_Insert_unprotected( (Chain_Node *)current, &the_thread->Object.Node );
+ _Scheduler_simple_Insert_priority_lifo( ready, the_thread );
}