/*! @file
* @brief Check how rtems_bdbuf_read() and rtems_bdbuf_release_modified()
* coexist. rtems_bdbuf_read() is blocked when required buffer is being
* transferred.
*
* The same as Test 2.1, but on step 7 thread #2 calls
* rtems_bdbuf_release_modified().
*
* Test sequence:
* -# Call rtems_bdbuf_read() function in thread #1 and block on
* waiting for read complete notification.
* -# Call rtems_bdbuf_read() function in thread #2 for
* the same block number. As the result it blocks on this read
* as well (but it will block on transfer semaphore).
* -# Disk device reports success in read complete notification.
* As the result rtems_bdbuf_read() function returns
* RTEMS_SUCCESSFUL in thread #1.
* -# Thread #1 releases buffer with rtems_bdbuf_release_modified() function.
* -# rtems_bdbuf_read() function in thread #2 unlocks and
* returns RTEMS_SUCCESSFUL.
* -# Wait swapout period and check that the buffer is not requested
* to be flushed to a disk.
* -# Call rtems_bdbuf_release_modified() function in thread #2.
* -# Check that this block number is requested for a flush in swapout period.
*
* Copyright (C) 2010 OKTET Labs, St.-Petersburg, Russia
* Author: Oleg Kravtsov <Oleg.Kravtsov@oktetlabs.ru>
*
* The license and distribution terms for this file may be
* found in the file LICENSE in this distribution or at
* http://www.rtems.com/license/LICENSE.
*
* $Id$
*/
#ifdef HAVE_CONFIG_H
#include "config.h"
#endif
#include <bdbuf_tests.h>
static rtems_task bdbuf_test2_2_thread1(rtems_task_argument arg);
static rtems_task bdbuf_test2_2_thread2(rtems_task_argument arg);
/* Block number used in the test */
#define TEST_BLK_NUM 70
void
bdbuf_test2_2_main()
{
bdbuf_test_msg msg;
TEST_START("Test 2.2");
START_THREAD(1, bdbuf_test2_2_thread1);
START_THREAD(2, bdbuf_test2_2_thread2);
/*
* Step 1:
* Thread #1 calls rtems_bdbuf_read() and we block
* this thread on data transfer operation.
*/
WAIT_DRV_MSG(&msg);
/*
* Step 2:
* Thread #2 calls rtems_bdbuf_read() for the same
* block number, as the result it shall block waiting
* on buffer state change (waiting on TRANSFER state).
*/
CONTINUE_THREAD(2);
/* Make sure thread #2 managed to block on the buffer. */
CHECK_THREAD_BLOCKED(2);
/*
* Step 3:
* Unblock thread #1 by reporting successful data transfer result.
*/
SEND_DRV_MSG(0, 0, RTEMS_SUCCESSFUL, 0);
/*
* Wait for sync from thread #1.
*/
WAIT_THREAD_SYNC(1);
TEST_CHECK_RESULT("3");
/* Check thread #2 is still blocked */
CHECK_THREAD_BLOCKED(2);
/*
* Step 4:
* Thread #1 releases buffer with bdbuf_release_modified() call.
*/
CONTINUE_THREAD(1);
/*
* Step 5:
* On buffer release operation, we should have unblock
* of thread #2 that is waiting on read buffer operation.
*/
WAIT_THREAD_SYNC(2);
TEST_CHECK_RESULT("5");
/*
* Step 6:
* Wait swapout period and check that there is no
* request to flush buffer onto a disk.
*/
CHECK_NO_DRV_MSG();
/*
* Step 7:
* Thread #2 releases buffer with bdbuf_release_modified() call.
*/
CONTINUE_THREAD(2);
/*
* Step 8:
* Check that in swapout interval disk device
* driver is requested to flush buffer.
*/
WAIT_DRV_MSG_WR(&msg);
SEND_DRV_MSG(0, 0, RTEMS_SUCCESSFUL, 0);
TEST_END();
}
static rtems_task
bdbuf_test2_2_thread1(rtems_task_argument arg)
{
rtems_status_code rc;
rtems_bdbuf_buffer *bd = NULL;
/*
* Step 1 - 3:
* Try to read blk #N on thread #1
* We will block on this read and meanwhile
* thread #2 will try to read the same block.
* After blocking on read in thread #2, device
* driver will notify successful completion of
* date transfer, and as the result this call
* will return valid buffer.
*/
rc = rtems_bdbuf_read(test_dd, TEST_BLK_NUM, &bd);
if (rc != RTEMS_SUCCESSFUL)
{
TEST_FAILED();
}
CONTINUE_MAIN(1);
/*
* Step 4:
* Release buffer returned on the previous step.
*/
rc = rtems_bdbuf_release_modified(bd);
if (rc != RTEMS_SUCCESSFUL)
{
TEST_FAILED();
}
THREAD_END();
}
static rtems_task
bdbuf_test2_2_thread2(rtems_task_argument arg)
{
rtems_status_code rc;
rtems_bdbuf_buffer *bd = NULL;
WAIT_MAIN_SYNC(2);
/*
* Step 2:
* Try to read block #N. Right now thread #1 is waiting
* on data transfer operation, so we will block here as well.
*
* Step 5:
* On step 4 thread #1 releases buffer and as the result
* our read operation should finish with success.
*/
rc = rtems_bdbuf_read(test_dd, TEST_BLK_NUM, &bd);
if (rc != RTEMS_SUCCESSFUL)
{
TEST_FAILED();
}
CONTINUE_MAIN(2);
/*
* Step 7:
* Release buffer.
*/
rc = rtems_bdbuf_release_modified(bd);
if (rc != RTEMS_SUCCESSFUL)
{
TEST_FAILED();
}
THREAD_END();
}
