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+ASCIIMathML Formulae
+====================
+
+http://www1.chapman.edu/~jipsen/mathml/asciimath.html[ASCIIMathML] is
+a clever JavaScript written by Peter Jipsen that dynamically
+transforms mathematical formulae written in a wiki-like plain text
+markup to http://www.w3.org/Math/[MathML] markup which is displayed as
+standard mathematical notation by the Web Browser.  See 'Appendix E'
+in the AsciiDoc User Guide for more details.
+
+The AsciiDoc `xhtml11` backend supports ASCIIMathML -- it links the
+ASCIIMathML script and escapes ASCIIMathML delimiters and special
+characters to yield valid XHTML. To use ASCIIMathML:
+
+1. Include the `-a asciimath` command-line option when you run
+   `asciidoc(1)`.
+2. Enclose ASCIIMathML formulas inside math or double-dollar
+   passthroughs or in math passthrough blocks.
+
+Here's the link:asciimathml.txt[AsciiDoc source] that generated this
+page.
+
+.NOTE
+- When you use the `asciimath:[]` inline macro you need to escape `]`
+  characters in the formulas with a backslash, escaping is unnecessary
+  if you use the double-dollar macro (for examples see the second
+  formula below).
+- See the
+  http://www1.chapman.edu/~jipsen/mathml/asciimath.html[ASCIIMathML]
+  website for ASCIIMathML documentation and the latest version.
+- If the formulas don't appear to be correct you probably need to
+  install the correct math fonts (see the
+  http://www1.chapman.edu/~jipsen/mathml/asciimath.html[ASCIIMathML]
+  website for details).
+- See the link:latexmathml.html[LaTeXMathML page] if you prefer to use
+  LaTeX math formulas.
+
+A list of example formulas:
+
+- $$`[[a,b],[c,d]]((n),(k))`$$
+- asciimath:[x/x={(1,if x!=0),(text{undefined},if x=0):}]
+- asciimath:[d/dxf(x)=lim_(h->0)(f(x+h)-f(x))/h]
+- +++`sum_(i=1)\^n i=(n(n+1))/2`$+++ and *bold
+  asciimath:[int_0\^(pi/2) sinx\ dx=1]*
+- asciimath:[(a,b\]={x in RR : a < x <= b}]
+- asciimath:[x^2+y_1+z_12^34]
+
+*********************************************************************
+The first three terms factor to give
+asciimath:[(x+b/(2a))^2=(b^2)/(4a^2)-c/a].
+
+asciimath:[x+b/(2a)=+-sqrt((b^2)/(4a^2)-c/a)].
+
+Now we take square roots on both sides and get
+asciimath:[x+b/(2a)=+-sqrt((b^2)/(4a^2)-c/a)].
+Finally we move the asciimath:[b/(2a)] to the right and simplify to
+get the two solutions:
+*asciimath:[x_(1,2)=(-b+-sqrt(b^2-4ac))/(2a)]*.
+
+*********************************************************************
+