/*! @file * @brief Check how read/release work in case of only one buffer in ready list. * * Test sequence: * -# In thread #1 call rtems_bdbuf_get(#N) to get an empty block #N. * -# In thread #1 call rtems_bdbuf_release_modified() for previously * got buffer. * -# In thread #1 call rtems_bdbuf_read(#N) to get the same buffer * (after this call a buffer is in AVL tree with ACCESS_MODIFIED state). * -# In thread #2 call rtems_bdbuf_read/get(#M). * -# In thread #1 call rtems_bdbuf_release(#N). * -# Check that in thread #2 a buffer is obtained. * * Copyright (C) 2010 OKTET Labs, St.-Petersburg, Russia * Author: Oleg Kravtsov * * The license and distribution terms for this file may be * found in the file LICENSE in this distribution or at * http://www.rtems.org/license/LICENSE. */ #ifdef HAVE_CONFIG_H #include "config.h" #endif #include "bdbuf_tests.h" static rtems_task bdbuf_test3_1_thread1(rtems_task_argument arg); static rtems_task bdbuf_test3_1_thread2(rtems_task_argument arg); /* Block number used in the test */ #define TEST_BLK_NUM_N 80 #define TEST_BLK_NUM_M 85 void bdbuf_test3_1_main() { bdbuf_test_msg msg; TEST_START("Test 3.1"); START_THREAD(1, bdbuf_test3_1_thread1); START_THREAD(2, bdbuf_test3_1_thread2); /* * Step 1-3: * Wait for sync from thread #1. * Thread #1 switch a buffer for #N into ACCESS_MODIFIED state. */ WAIT_THREAD_SYNC(1); TEST_CHECK_RESULT("3"); /* * Step 4: * Thread #2 calls get() function and blocks * (there no buffers available in bdbuf library). */ CONTINUE_THREAD(2); /* Make sure thread #2 managed to block on the buffer. */ CHECK_THREAD_BLOCKED(2); /* * Step 6: * Thread #1 release buffer. */ CONTINUE_THREAD(1); /* * Buffer released in thread #1 was in MODIFIED state, so * there will be a request for disk write */ WAIT_DRV_MSG_WR(&msg); SEND_DRV_MSG(0, 0, RTEMS_SUCCESSFUL, 0); /* * Check that thread #2 unblocked after this. */ WAIT_THREAD_SYNC(2); TEST_CHECK_RESULT("5"); /* * Release buffer in thread #2 */ CONTINUE_THREAD(2); /* * Buffer released in thread #2 switched to MODIFIED state, so * there will be a request for disk write */ WAIT_DRV_MSG_WR(&msg); SEND_DRV_MSG(0, 0, RTEMS_SUCCESSFUL, 0); TEST_STOP(); } static rtems_task bdbuf_test3_1_thread1(rtems_task_argument arg) { rtems_status_code rc; rtems_bdbuf_buffer *bd = NULL; /* * Step 1: * Call rtems_bdbuf_get(#N) to get an empty block db; * [this call will remove a buffer from ready list and insert * it in AVL tree with ACCESS state. * Step 2: * Call release_modified(bd); * [Now we have one entry in modified list and it is still * in AVL tree with MODIFIED state] * Step 3: * Call read(#N) to get the same buffer. * [An entry is found in AVL tree, removed from modified list and * returned with state ACCESS_MODIFIED] */ rc = rtems_bdbuf_get(test_dd, TEST_BLK_NUM_N, &bd); if (rc != RTEMS_SUCCESSFUL) { TEST_FAILED(); } rc = rtems_bdbuf_release_modified(bd); if (rc != RTEMS_SUCCESSFUL) { TEST_FAILED(); } rc = rtems_bdbuf_read(test_dd, TEST_BLK_NUM_N, &bd); if (rc != RTEMS_SUCCESSFUL) { TEST_FAILED(); } CONTINUE_MAIN(1); /* Step 5: * Call rtems_bdbuf_release(#N). * As the result buffer will be used by bdbuf to get * buffer #M for thread #2. */ rc = rtems_bdbuf_release(bd); if (rc != RTEMS_SUCCESSFUL) { TEST_FAILED(); } THREAD_END(); } static rtems_task bdbuf_test3_1_thread2(rtems_task_argument arg) { rtems_status_code rc; rtems_bdbuf_buffer *bd = NULL; WAIT_MAIN_SYNC(2); /* * Step 4: * In thread #2 call read/get(#M) * [We ask for block number #M - there is no such entry in AVL, * and all the lists are empty (ready, lru, modified), as a result * this thread blocks on * rtems_bdbuf_wait(pool, &pool->waiting, &pool->wait_waiters)] */ rc = rtems_bdbuf_get(test_dd, TEST_BLK_NUM_M, &bd); if (rc != RTEMS_SUCCESSFUL) { TEST_FAILED(); } CONTINUE_MAIN(2); /* * Release buffer. */ rc = rtems_bdbuf_release_modified(bd); if (rc != RTEMS_SUCCESSFUL) { TEST_FAILED(); } THREAD_END(); }